Today we went over factoring a quadratic polymonial in the form of ax^2 + bx + c. Compared with the last lesson where we talked about factoring x^2 + bx + c, we are introducing the “a” (non 1) for the X
\nsquare term.<\/p>\n
For it to be able to factor into the form of (mx + p)(nx + q), then:<\/p>\n
a = mn
\nc = pq
\nb = mq + np<\/p>\n
One way to work it out is to list the a’s factors m and n, along with c’s factors p and q in a matrix form: We practiced this with several questions in the classroom. This will take some more practice to get good at.<\/p>\n We then talked about factoring out a polynomial completely. We talked about factoring a polynomial like the following:<\/p>\n x^3 -2x^2 -9x + 18 We went over some more questions from the math contest.<\/p>\n There will be no school for the next two Sundays (4\/17 and 4\/24). Enjoy the Easter and the April break.<\/p>\n","protected":false},"excerpt":{"rendered":" Today we went over factoring a quadratic polymonial in the form of ax^2 + bx + c. Compared with the last lesson where we talked about factoring x^2 + bx + c, we are introducing the “a” (non 1) for the X square term. For it to be able to factor into the form of […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"ngg_post_thumbnail":0},"categories":[9,3],"tags":[],"_links":{"self":[{"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/posts\/86"}],"collection":[{"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/comments?post=86"}],"version-history":[{"count":7,"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/posts\/86\/revisions"}],"predecessor-version":[{"id":94,"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/posts\/86\/revisions\/94"}],"wp:attachment":[{"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/media?parent=86"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/categories?post=86"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/blog.newtonchineseschool.org\/wangweidong\/wp-json\/wp\/v2\/tags?post=86"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n
\nm\u00a0\u00a0\u00a0\u00a0 p
\n X
\nn\u00a0\u00a0\u00a0\u00a0 q
\n<\/code>
\nThe sum of of the cross-product mq + np must be equal to b.<\/p>\n
\n= x^2 (x – 2) -9(x – 2)
\n= (x – 2)(X^2 – 9)
\n= (x – 2)(x – 3)(x + 3)<\/p>\n